nodrog19 - 15-6-2008 at 19:49
"distillation gives an azeotrope with a concentration of 68% HNO3 and a boiling temperature of 120.5 °C."
What molarity is this?
Does is mean 68 mol HNO3 +32mol H2O?
Also, if all the Sulfuric acid is removed from 57.7ml of 17.311 molar (93.2%), should 6.8% volume of water be left?
[Edited on 15-6-2008 by nodrog19]
Magpie - 15-6-2008 at 21:02
Molarity is moles/liter. The % is weight % for both acids.
To calculate molarity for the nitric you need its density. For 68% nitric my handbook says density = 1.40.
So the weight of a liter is 1400g, and the weight of HNO3/liter is = (0.68)(1400g) = 968g
MW = 63.01
Molarity = 968g/(63.01g/mole) = 15.4
Same kind of routine for the sulfuric acid.
[Edited on 15-6-2008 by Magpie]
nodrog19 - 16-6-2008 at 08:30
Thank you very much
What is the density for 60% HNO3?
[Edited on 16-6-2008 by nodrog19]
nodrog19 - 16-6-2008 at 08:42
never mind, its 1.367
molarity=13.02
[Edited on 16-6-2008 by nodrog19]