Opylation - 2-12-2019 at 11:09
Hello everyone,
The question is in the title, I am curious if the haloform reaction will commence with a monochloro substituted methyl ketone, or 2, for that matter.
Theoretically which ever side gets a second chlorine group would then be subject to the 3rd chlorination and then the final step of the haloform
reaction creating Chloroform and sodium chloroacetate. Am I right or not?
I’m thinking one could use a hypochlorite instead of chlorine and a base to trim down the process. That would limit the possibilities for side
reactions hmmmmmm?
Just curious, let me know whatcha think!
Cou - 2-12-2019 at 12:15
That could work, but I dont know how to make bis chloromethyl ketone. I think an OTC route to chloroacetic acid would be to make 2-chloroethanol from
ethylene glycol and anhydrous HCl + ZnCl2, then oxidize with jones reagent to chloroacetic acid
Fery - 2-12-2019 at 15:33
high purity monochloroacetic acid was prepared by hydrolysis of trichlorethylene catalyzed by H2SO4
trichlorethylene was commonly used solvent 20 years ago, but seems to be abandoned now, pitty
https://www.umweltbundesamt.de/sites/default/files/medien/51...
draculic acid69 - 2-12-2019 at 22:09
Isn't it made via chlorination of gaa with an i2 catalyst which gives it a pinkish hue?
Read this somewhere I think.
Amos - 3-12-2019 at 11:45
The OP could find the routes all of your are suggesting if they wanted to, better stick to the topic at hand.