Merryp - 26-2-2020 at 04:41
Since the Sulfide anion shouldn't exist in solution, I'd assume both form HS-, and eventually, H2S.
Is that correct, and if so, would there be any major differences in reaction speed, stability, etc?
Tsjerk - 26-2-2020 at 05:44
Although the sulfide ion doesn't exist, a solution of sodium sulfide is much more basic compared to sodium hydrogen sulfide.
Sodium hydrogen sulfide forms no hydroxide when dissolving, not much at least, sodium sulfide forms around an equimolar amount of hydroxide.