What oxidizing agent is consumed?
Quote: | // air oxidation?
2C₂H₅OH + O₂ -> 2CH₃CHO + 2H₂O //catalyzed by UO₂²⁺
// oxidation by excess nitric acid?
C₂H₅OH + UO₂(NO₃)₂ + 2HNO₃ -> 2CH₃CHO + U(NO₃)₄ + 2H₂O
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The paper suggests that uranium(IV) is a product of the reaction, so I presume that some variation of the latter formula occurs.
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