rocketscience - 25-11-2004 at 19:06
I was wondering if NH4OH and NaClO4 would react to form NH4ClO4 and NaOH
budullewraagh - 25-11-2004 at 19:25
nope
BromicAcid - 25-11-2004 at 19:49
Well, as always if you're talking about an aqueous solution then there is an equilibrium present, the ions are really just floating around with
no major loyalty to each other, so you have:
NaClO4(aq) + NH4OH(aq) <---> NaOH(aq) + NH4ClO4(aq)
10.74 g NH4ClO4 soluble in 100 ml Cold water
89.9 g NH3 soluble in 100 ml Cold water
209 g NaClO4*H2O soluble in 100 ml cold water
42 g NaOH soluble in 100 ml cold water
Based on solubility, a saturated solution of ammonium hydroxide mixed with a saturated solution of sodium perchlorate will yield a precipitate of
ammonium perchlorate. There is one little hang up though, concentrated NaOH solutions will react with ammonium salts to yield ammonia gas and the
corresponding sodium salt and water:
NaOH(aq) + NH4ClO4(aq) ---> NaClO4(aq) + NH3(g) + H2O(l)
But if you keep the solution cold you should be able to keep the equilibrium where you want it. The long and the short of it says though that it is
possible theoretically.
rocketscience - 25-11-2004 at 20:06
So in other words it’s not a good way. But what if co2 or some other substance was present could a reaction occur I know that ammonia + brine +
carbon dioxide = sodium bicarbonate + ammonium chloride + h20
(I don’t think that co2 would affect it)
vulture - 26-11-2004 at 09:08
This reaction won't work for the simple fact that NaOH is a much stronger base than ammonia.
Furthermore, if you're not aware of this, you shouldn't be messing with these chemicals!
You also might want to do something about your posts, a bit of effort would be the least you can do. 
nh4clo4 - 27-11-2004 at 15:21
If you really need nh4clo4 you can mix nh4no3 and naclo4 it will then form nh4clo4 and nano3 witch can then they can be separated by solubility in h2o
you should do google searches there is tons of info