kclo4 - 2-4-2005 at 13:07
i cant find it any were i can't even find any hydrates of ammonium nitrate
vulture - 2-4-2005 at 13:14
I've warned you before, put more effort in your posts and make them coherent!
Next time is sanction time.
Now what the hell are you trying to say anyway?
kclo4 - 2-4-2005 at 13:34
i am asking what is the maximum hydrate of ammonium nitrate at room temperature
sorry for being ignorant
hodges - 2-4-2005 at 14:18
I believe that since ammonium nitrate is hygroscopic, it will absorb an indefinite amount of water from the air.
JohnWW - 2-4-2005 at 14:55
Ammonium nitrate crystallizes with no water of crystallization, at any temperature. Neither the ammonium nor the nitrate ion hydrogen-bond water
molecules sufficiently strongly. There are, however, two different crystalline forms, one of which (alpha, tetragonal) crystallizes at -16 to 32ºC,
and the other (beta, monoclinic) at 32ºC to 84ºC. Both decompose explosively at 210ºC.
The only nitrates that crystallize with water of crystallization are those in which the H2O is bonded as a ligand to the metal cation sufficiently
strongly, e.g. Cd(NO3)2.4H2O, Ca(NO3)2.4H2O, Cu(NO3)2.3H2O and Cu(NO3)2.6H2O, Fe(NO3)2.6H2O, Fe(NO3)3.6H2O, Ni(NO3)2.6H2O, Zn(NO3)2.6H2O,
Al(NO3)3.9H2O, Bi(NO3)3.5H2O, LiNO3.3H2O, Mn(NO3)2.6H2O, Hg2(NO3)2.2H2O. Most other metal nitrates are anhydrous.
[Edited on 2-4-2005 by JohnWW]
NH4NO3
MadHatter - 3-4-2005 at 01:59
Kclo4, what references are you looking at ? I see no hydrate versions of ammonium
nitrate in any of my CRCs. I have the 52nd, 62nd, and 81st editions. If you haven't
already done so, go to a used book store or eBay and find an edition. If you can't afford
it, local libraries tend to have an edition or 2 on hand. BTW, I paid only $15(USD) for
the 52nd edition at a local used book store.
BASF - 3-4-2005 at 03:42
In case you are needing this info for stoicheometric calculations you might also consider the big amount of adsorbed water. I think this can be very
well in the magnitude of 50% of the total weight ... but this is very difficult to just calculate