acx01b - 4-11-2005 at 15:12
hi,
i dont think this is already posted:
if i try making para toluene sulphonic acid by refluxing
toluene and 90% h2so4 (2mol h2so4 for 1mol h2o)
C6H5CH3 + 2H2SO4 + H2O will i get CH3C6H5HSO3.H2O + H3OHSO4
or will the yield be poor ????
this suggesting that in the reaction, the H3OHSO4 in my 90% sulphuric acid would act as a spectator...
ty
[Edited on 5-11-2005 by chemoleo]
hydrargirum - 4-11-2005 at 20:13
Preparation p-toluenesulphonic acid: it is necessary to operate to temperature
on 100ºC (around 170ºC), it must have an excess of toluene to avoid disulphonation, in addition it must bubble a slow airflow to mix well both
phases while the reflux of the mixture is made.
To temperatures under 100ºC is obtained o- and m- isomers (to 0ºC up to 45% of o-)
acx01b - 6-11-2005 at 03:50
this doesn't answer at all because my question was more about the sulphonation power of a non 100% sulphuric acid.... but ty
bio2 - 7-11-2005 at 01:49
If water is azeotropically removed during the sulphonation less than concentrated acid will work satisfactorily.
Just how dilute the sulfuric may be I can't say. Benzene is used as entrainer if the temp needs to be kept below PhMe boiling point.
Seems there is a thread on this subject in the forum IIRC.