My words are hard to translate. I think PHILOU may be able to understand them and smile
What I meant with my last sentence is that making oxybromide (and also oxychloride) from CuO and the corresponding acid is not possible in those
acidic solutions.
If you use excess acid, then all CuO dissolves to form the halide and the strongly colored tetrahalogen complex of copper (which is deep yellow/brown
for chloride and nice purple/red/brown for bromide). If you use excess CuO, then you get a solution of the copper halide and some CuO remains
undissolved.
Could you separate the oxide from the mix by using string mineral acid? HCl? May seem like a stupid question but when you get to it..?
Making oxyhalide can be done by preparing a solution of the copper halide and then carefully adding (under constant strong stirring) hydroxide. This
will give you a compound of ill-defined composition, with halide ions and hydroxide ions mixed in the compound. Heating this stuff drives off water
and leaves behind a mixed halide/oxide.
Another option is to prepare wet CuCl or CuBr. These are white solids and can be prepared from HCl/HBr, copper oxide and a sulfite or metabisulfite.
The wet solid must be rinsed with water and then the humid compound must be put aside in contact with air. It will oxidize quickly and lose its white
color. When it is dry, you need to grind very well and allow to stand in contact with air for another few days. Finally you end up with a dry,
non-hygroscopic powder. The mixed oxide/chloride is green (not blue at all), I expect the mixed oxide/bromide to be green as well, probably a somewhat
darker shade, green like olives. But this is my educated guess, I have no personal experience with that. If you use a sulfite/metabisulfite, use the
potassium salt, such as K2S2O5. If you use the sodium salt, then the resulting copper oxide/halide also has some sodium ions in it, which spoils the
blue color of the flame. |