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Author: Subject: stoichiometry question
EnvSciMOOSE
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biggrin.gif posted on 11-9-2005 at 17:11
stoichiometry question


Quick question on the setup of this problem, where do i start with these numbers??:

Calculate the catechol (substrate) concentration of a solution prepared by mixing:

18 drops 0.01M catechol + 2 drops water (assume 20 drops = 1mL)
8mL Deionized water
1.0 mL aqueous enzyme extract

thank you!!
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[*] posted on 11-9-2005 at 20:04


Assuming you want it as a molarity:

M1V1 = M2V2

M2 = (M1V1)/V2 = [(0.01)(18/20)]/(18/20 +2/20 +8 +1)

BTW this is not stoichiometry but a concentration calculation.




The single most important condition for a successful synthesis is good mixing - Nicodem
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