littlepike3
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LPG combustion question
Hello everyone, I am the currently the newest new guy. This looks like a good discussion board (just finished enjoying the discussion of shaped
charges).
I'm a college student (College of the Ozarks, Missouri) with no background in chemistry besides highschool stuff. I am working on designing a
recreational project. Basically it will involve a small cyclical apparatus (which I haven't fully designed yet) powered by a propylene/butylene
(65%C3H6/35%C4H8) mixture combustion reaction.
Propylene combustion - 2C3H6 + 9O2 -> 6CO2 + 6H20
Butylene combustion - C4H8 + 602 -> 4CO2 + 4H2O
I need to know how to compute the pressure/temperature produced by the reaction (in a fixed volume) in order to properly and safely design the rest of
my invention (which will hopefully turn out to be a better mousetrap, even if it's just for me).
Thanks a lot everyone,
-D
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12AX7
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Hum, I'd guess adiabatic flame temperature to be in the 3500°F range. Propane alone (C3H8) is around 3300-3400, IIRC.
I'm sure you know that's with everything perfect and that any realistic radiation loss will sap a lot.
Tim
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littlepike3
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Ok. So can I calculate pressure based on adiabatic flame temp?
P1*V1/T1 = P2*V2/T2
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vulture
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If your design has a nozzle in which the combustion occurs, yes. If combustion occurs outside your vessle/nozzle radiation and convective losses will
be immense.
One shouldn't accept or resort to the mutilation of science to appease the mentally impaired.
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