emrebjk
Hazard to Others
Posts: 108
Registered: 22-1-2005
Location: Zonguldak/TURKEY
Member Is Offline
Mood: No Mood
|
|
turnover number (TON) and turnover frequency(TOF)
Hi all
TON = (%conv) x (mol(substrat)) / mol (catalyst)
TOF = TON / time(h)
[Edited on 19-8-2009 by emrebjk]
|
|
|
behemoth
Harmless
Posts: 17
Registered: 19-8-2009
Member Is Offline
Mood: No Mood
|
|
TON = turn over number = molar ratio of converted substrate to catalyst
TOF = turn over frequency = TON per hour
example: 10 mmols of substrate are converted to product using a catalyst loading of 0.2 mmols in 2 hours .
TON = 10/0.2 = 50
TOF = 50/2 h = 25 h(-1)
[Edited on 19-8-2009 by behemoth]
[Edited on 20-8-2009 by behemoth]
[Edited on 20-8-2009 by behemoth]
|
|
|
emrebjk
Hazard to Others
Posts: 108
Registered: 22-1-2005
Location: Zonguldak/TURKEY
Member Is Offline
Mood: No Mood
|
|
catalyst = 6x10 -3
[substrat]/[cat] = 2900
%conv = %60
They said TON = 1745, I could't calculate it.
[Edited on 19-8-2009 by emrebjk]
|
|
|
behemoth
Harmless
Posts: 17
Registered: 19-8-2009
Member Is Offline
Mood: No Mood
|
|
Ok. Its the molar ratio of converted substrate to catalyst, to correct myself. In your example: 2900 is the ratio of substrate to catalyst. Only 60%
of the substrate are converted to product, i.e. TON is only 60% of the 2900.
2900 * 0.6 = 1740
[Edited on 20-8-2009 by behemoth]
|
|
|
![[*]](images/xpblue/default_icon.gif){kind=icon}
