michalJenco
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Synthesis of NaI from KI - how to wash away KOH?
Hi fellow chemists.
I want to do some Finkelstein reactions in acetone but only have potassium iodide. Therefore I converted it by following the equation:
KI + NaOH --> NaI + KOH
I didn't realize, however, that my product would remain basic from KOH and I can't figure out how to wash the base away without .. you know ..
dissolving my product.
Does this make the route impossible or am I missing something? The base would obviously cause acetone to self-condense so I'm not even trying to work
with the base-contaminated stuff.
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karlos³
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Mood: oxazolidinic 8)
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If you haven't done the stoichiometry correctly and still have KOH left... well, then neutralise it!
You can take advantage of the solubility of NaI in acetone I guess.
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draculic acid69
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Neutralise to p.h.7 with vinegar evaporate to dryness and extract with acetone.im assuming potassium acetate is insoluble in acetone but I get the
feeling it is. I would avoid HCL as adding HCL to iodide salts changes colour and does weird things in my experience.
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draculic acid69
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Just looked it up and yep it's insoluble
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Fery
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something similar discussed here:
https://www.sciencemadness.org/whisper/viewthread.php?tid=15...
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