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Author: Subject: Lead 2 acetate basic
dextro88
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[*] posted on 14-9-2020 at 11:50
Lead 2 acetate basic


Hello,
I want to synthese some lead diacetate by combining one mole of Lead
oxide and 2 moles of acetic acid, but was wondering, will the produced
lead 2 acetate be the basic one or the tryhidrate as i need the more
thermo stable one.

Regards.

[Edited on 14-9-2020 by dextro88]
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njl
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[*] posted on 15-9-2020 at 10:15


If you use dry reagents and don't conduct the reaction in water then the product will be dry. If your reagents aren't dry (aqueous acetic acid for example) then you will either end up with the hydrate or a mix of the hydrates and anhydrous form depending on how much water is present. Bbuuuttttt basic lead acetate is not the same as lead acetate hydrate. When a salt is "basic" as in basic copper carbonate or basic lead acetate, it means that the compound is a mixed salt with at least one cation being OH- and the others being, well, anything else. This is just my basic understanding of the concept so I'm sure other people could be more helpful. Do you want basic lead acetate?
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dextro88
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[*] posted on 15-9-2020 at 12:52


thanks for your input, i already thought this,
but that mean i will need atlest some water in there to be able to donate OH atoms, but that will lead to some byproduct as the tryhidrade in the mixture, maybe i need to try out both anhydrous procedure and a little bit wet one, and will try out a destructive decarboxilation of phenylcarboxilic acid, and yield will tell, any more wise ideas ?

Actualy i cheked both molecules :
https://pubchem.ncbi.nlm.nih.gov/compound/Lead_II_-acetate-b...
https://pubchem.ncbi.nlm.nih.gov/compound/Lead-acetate-trihy...

and find out the tryhidrate is just with 3 OH cations, and the basic one have just 2, so that mean i will need to dilute the acetic acid with 2 moles H2O per mole of PbO, i am right ?

Regards


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B.D.E
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[*] posted on 16-9-2020 at 05:17


Quote: Originally posted by dextro88  

but that mean i will need atlest some water in there to be able to donate OH atoms

Pretty sure the net reaction goes something like that: PbO + 2AcOH --> Pb(OAc)2 + H2O. So there's probably no need for OH ions in order for the reaction to take place.

Also note that the reaction forms water as a byproduct, so you probably won't get anhydrous product even in anhydrous conditions. Luckily, Pb(OAc)2 is really easy to dry, just put it in the oven and wait(it won't decompose till ~176C)[1].

Lastly, as long as you use acetic acid, I don't think it's likely for any basic salts to be formed in the reacrion.

[1] - https://pubs.acs.org/doi/10.1021/acs.inorgchem.6b01116
Screenshot_20200626_173809.jpg - 200kB


[Edited on 16-9-2020 by B.D.E]




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B.D.E
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[*] posted on 16-9-2020 at 05:23


Quote: Originally posted by dextro88  

and find out the tryhidrate is just with 3 OH cations, and the basic one have just 2, so that mean i will need to dilute the acetic acid with 2 moles H2O per mole of PbO, i am right ?
Check again. There's 3 water molecules, not 3 OH ions.




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DraconicAcid
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[*] posted on 16-9-2020 at 08:32


I think if you don't know the difference between hydroxide ions and water molecules, you might want to put off messing with lead salts until you've got a better grasp of chemistry.



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Write up your lab reports the way your instructor wants them, not the way your ex-instructor wants them.
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dextro88
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[*] posted on 16-9-2020 at 09:06


Quote: Originally posted by B.D.E  
Quote: Originally posted by dextro88  

and find out the tryhidrate is just with 3 OH cations, and the basic one have just 2, so that mean i will need to dilute the acetic acid with 2 moles H2O per mole of PbO, i am right ?
Check again. There's 3 water molecules, not 3 OH ions.


actualy i dont see good on the picture and was thinking abaut these OH ions njl was talking, and posted too fast, was thinking abaut whole another way of mechanism, where water will donate OH ions to the acetate salt and was wondering how this will happen in these acidic conditions.

But, thanks to B.D.E for the kind answer, that clarify a lot of thoughts i was having, so simply stiring the melted salt at high temperatures will dehydrate to the basic salt as i understand.

And last, i know the toxicty of lead salts and espesily the lead diacetate, and its usage in history and and all tested toxicity, i got natural solution for such reactions ;)

[Edited on 16-9-2020 by dextro88]
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njl
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[*] posted on 17-9-2020 at 08:48


It seems like your question was answered but I have no idea what your last response means. Just make sure you wear gloves/goggles and have some water nearby to thoroughly wash any spills.
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yobbo II
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[*] posted on 20-9-2020 at 13:05



See the 'Lead Salts preparation' thread for (perhaps more info)
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