Boffis
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Michler's Ketone
MIchler's Ketone is a well known component of several dyes and its preparation is described in several books on dye chemistry, eg Processes in dye
chemistry by Fierz-David & Blangey (SM library).
It is prepared by reacting carbonyl chloride (phosgene) with dimethylaniline... and there's the problem... phosgene. OK on an industrial plant but not
exactly amateur friendly.
Does anyone know of an alternative route? I was wondering if it is possibly to oxidize the appropriate bis(dimethylaminophenyl)methane which is
readily prepared from formaldehyde and dimethylaniline? The oxidation of tetrabase, the tetramethyldiaminodiphenylmethane, to the analogous hydrol
with lead dioxide is described in Fierz-David's book too so in theory it should be possible to oxidise it a little further to the ketone.
Anyone any ideas?
[Edited on 16-8-2022 by Boffis]
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digga
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https://patents.google.com/patent/US2231067A/en
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Lionel Spanner
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Carbonyl diimidazole might work as a substitute for phosgene, though it's less reactive.
Industrial chemist rediscovering the practical pleasures of pure chemistry.
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Dr.Bob
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Here are a variety of ways to make it, which include the oxidation of the methane to ketone, but there are a variety of ways to do it.
Sadly, while CDI is great for many things, it cannot do the Freidel-Crafts chemistry needed. Triphosgene would likely work, but also hard to find.
Attachment: MIchlersKetonePreps.pdf (387kB)
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Boffis
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Many thanks guys for the responses! My god Bob, some of those method in your scifinder download look complex, particularly the oxidation of the hydrol
to ketone route, is there any particular theoretical reason why they need such obscure oxidizing agents/conditions? I think I might just try a few
more accessible oxidizing agent first.
Also could there be a route through say dimethylaminobenzoic acid, perhaps via its acid chloride and a Friedel Craft type condensation with
dimethylaniline? This then raises the question of how to introduce the carboxylic acid group into the 4 position. I have recently recovered some
4-nitro dimethylaniline from another experiment so I could probably reduce it to the amine, then via the Sandmeyer route to the nitrile and hydrolysis
to the acid. Give the ease with which dimethylaniline undergoes substitution in the 4 position are there any more direct routes that any one can think
of?
Two other routes have just occurred to me. Does anyone think that the methylene group is reactive enough to react with either a nitroso group (say
nitrosodimethylaniline) or an alkyl nitrite to give the appropriate imine or oxime.
The second is the possibility of oxidizing the methylene group with sulphur to the thioketone and then de-sulphurisation as per the scifinder
references give in Dr. Bob's post.
[Edited on 19-8-2022 by Boffis]
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