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Author: Subject: NH4OH
kevinlimse
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[*] posted on 20-10-2004 at 02:57
NH4OH


Why is the Ammonium Hydroxide an improper name for aqueous ammonia?
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kyanite
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[*] posted on 20-10-2004 at 12:19


??? Don't those two go interchangeably because it's at an equilibrium? Or atleast in water: NH3 + H2O <--> NH4OH

My guess why ammonium hydroxide isn't the same would be the consetrations. Ammonium Hydroxide(assumed that it's in a pure, not mixture form) isn't the same consentration as aqueous ammonia, which would be NH3 dissolved, and would be at max about 30% NH3?




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[*] posted on 20-10-2004 at 12:51


Because ammoniumhydroxide doesn't exist and can't be isolated.

The correct rxn:

NH3 + H2O ----> NH4+ + OH- which are present as seperate ions.




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tom haggen
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[*] posted on 21-10-2004 at 10:12


So you if you have a synthesis that calls for a 5% (aq) solution of NH3 than you could simply use ammonium hydroxide. Also If you have a 100% (aq) NH3 is that the same as 100% NH4OH?



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[*] posted on 21-10-2004 at 10:53


100% NH3 can't contain anything else but NH3 and thus can't be a solution....



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tom haggen
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[*] posted on 22-10-2004 at 08:24


Okay, 99% then. Lets say you dissolve NH3 (g) into H20 up to a 99% concntration. Will it consist of NH4 ions and OH ions floating around in water? Or will there be some definite NH3 ions thrown in the mix? I don't know why but I've had a hard time understanding this concept for sometime now.

[Edited on 22-10-2004 by tom haggen]




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[*] posted on 22-10-2004 at 10:18


The equilibrium NH3 + H2O <---> NH4+ + OH- is situated to the left and even more so in concentrated solutions.

99% NH3 won't work either because that is just humid NH3 gas.




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tom haggen
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[*] posted on 22-10-2004 at 10:22


Ammonia is one slut of a chemical.
I guess I'm still only used to reactions that theoretically happen from left to right, maybe thats why i'm having such a hard time wrapping my head around this topic.



[Edited on 22-10-2004 by tom haggen]




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[*] posted on 22-10-2004 at 12:00


You should study equilibriums and then acid-base equilibriums, this will give you a much clearer view.

There are not many reactions that go fully to completion.




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