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Author: Subject: production of copper sulfate by electrolysis of ammonium bisulfate with copper electrodes
mysteriusbhoice
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[*] posted on 20-8-2016 at 07:42
production of copper sulfate by electrolysis of ammonium bisulfate with copper electrodes


i first electroylze it in aqueous solution with copper electrodes to produce copper sulfate.

then i dry it then i thermally decompose the ammonium bisulfate at 300 celsius.

only the copper sulfate will remain since it decomposes at 560 celsius

im gonna use it to produce sulfuric acid since i cant get a hold of it

ELECTROLYSIS VID:
https://youtu.be/jW_oJjs9YlI

[Edited on 21-8-2016 by mysteriusbhoice]

[Edited on 21-8-2016 by mysteriusbhoice]
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mysteriusbhoice
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[*] posted on 20-8-2016 at 07:48


what i worry is that it will react with the ammonia being given off while the ammonium bisulfate decomposes
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hissingnoise
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[*] posted on 20-8-2016 at 08:09


Quote:
i first electroylze it in aqueous solution then i dry it then i thermally decompose the ammonium bisulfate at 300 celsius

What does the sol. consist of, is the obvious question?

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mysteriusbhoice
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[*] posted on 20-8-2016 at 08:47


update somehow it is creating schweitzer's reagent ontop of the copper sulfate!!
seperating into 2 layers of blue and deeper blue

now boiling it off
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mysteriusbhoice
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[*] posted on 20-8-2016 at 08:48


Quote: Originally posted by hissingnoise  
Quote:
i first electroylze it in aqueous solution then i dry it then i thermally decompose the ammonium bisulfate at 300 celsius

What does the sol. consist of, is the obvious question?



before the electrolysis its a solution of ammonium bisulfate

after its a solution of copper sulfate and scweitzer's reagent ontop!!
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PHILOU Zrealone
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[*] posted on 20-8-2016 at 12:10


I don't understand what you write nor what you try to do...

Schweitzer's reagent is Cu(OH)2 or CuO dissolved into NH4OH (NH3 + H2O).

Heating NH4HSO4 will generate NH3 and H2SO4 (H2O + SO3) eventually via (NH4)2SO4 and H2SO4.

CuSO4 with NH3 will form Cu(NH3)4SO4 but this complex will be destroyed by the H2SO4 present.




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mysteriusbhoice
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[*] posted on 20-8-2016 at 14:50


Quote: Originally posted by PHILOU Zrealone  
I don't understand what you write nor what you try to do...

Schweitzer's reagent is Cu(OH)2 or CuO dissolved into NH4OH (NH3 + H2O).

Heating NH4HSO4 will generate NH3 and H2SO4 (H2O + SO3) eventually via (NH4)2SO4 and H2SO4.

CuSO4 with NH3 will form Cu(NH3)4SO4 but this complex will be destroyed by the H2SO4 present.


i thought that too but while i was electrolysing B4 the heating!!
i saw a seperate dark blue layer ontop and was confused and it the cell was giving off an ammonia smell!!

it was ontop of the copper sulfate layer!!

but it dissapeared when i mixed it and the smell is gone

i will soon include pictures when i repeat this experiment tomorrow

[Edited on 20-8-2016 by mysteriusbhoice]

[Edited on 20-8-2016 by mysteriusbhoice]
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Jstuyfzand
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[*] posted on 20-8-2016 at 15:14


Doesnt bisulfate electrolysis yield Persulfate which hydrolyses into H2O2?
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mysteriusbhoice
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[*] posted on 21-8-2016 at 02:42


Quote: Originally posted by Jstuyfzand  
Doesnt bisulfate electrolysis yield Persulfate which hydrolyses into H2O2?


it doesnt yield that and im using copper electrodes!! so it yields copper sulfate

also im using ammonium bisulfate/ammonium sulfate apparently i get the same result in the end with the latter running longer

WHY DOESNT ANYONE READ B4 COMMENTING
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hissingnoise
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[*] posted on 21-8-2016 at 03:28


You're the one who most needs to do some reading ─ more reading will make you sound less like an asshole!

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[*] posted on 21-8-2016 at 03:39


It would be far more construcive if you wrote actual reactions, including anode/ cathode half-reactions during the electrolysis. Until then there is little I can do.
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