| Pages:
1
2 |
Fulmen
International Hazard
Posts: 1693
Registered: 24-9-2005
Member Is Offline
Mood: Bored
|
|
Not sure, it didn't factor in to my answer. I calculated how to get the unit it's design pressure based on a given altitude, that's all.
We're not banging rocks together here. We know how to put a man back together.
|
|
|
moray james
Harmless
Posts: 11
Registered: 22-9-2016
Member Is Offline
Mood: No Mood
|
|
I have access to one of those laser thermometers Can I simply shoot my pot when it is cooking and take measurements with each of the two regulators I
have (2.7 ounces and 3 ounces available)? While I am asking do I shoot the top of the pot or would shooting the water vapor escaping the regulator be
the best option? Thanks for the help.
[Edited on 27-9-2016 by moray james]
|
|
|
BillA
Harmless
Posts: 1
Registered: 5-12-2017
Member Is Offline
Mood: No Mood
|
|
Weigths
Just for kicks and giggles I did a quick calc. My vent pipe top diameter is also 3/16, or .19". However that is not the effective area that the
pressure acts upon. If it were, you would need 6.7 oz to resist 15 psig. The .19" is only a lip that the weight rests on. The vent diameter under the
lip is only .12" diameter. With such a diameter and 15 psig pressure underneath (@ SL) you would need (.12/2)^2*3.14159*15 *16oz/lb=2.71 oz. Exactly
as supplied.
|
|
|
| Pages:
1
2 |
![[*]](images/xpblue/default_icon.gif){kind=icon}
