BeckhamStZ - 31-5-2006 at 00:56
I have a problem with one scheme:
C6H6 + Br2 -> A
A + 2NaOH -> B
B + HCl -> C
C + 3HNO3 -> D + 3H2O
I think that A is bromobenzen and the reaction is
C6H6 + Br2 -> C6H5Br + HBr
but what is B!? is that true :
C6H5Br + 2NaOH -> C6H5ONa +NaBr +H2O
or not??? ![:o](./images/smilies/shocked.gif)
Joeychemist - 31-5-2006 at 02:23
Wow, and interesting homework question, for onceā¦
To give you a hint;
Your end product will be 2,4,6,-Trinitrophenol...![;)](./images/smilies/wink.gif)
Edit: Chlorobenzene with also work in that reaction, good to know.![:)](./images/smilies/smile.gif)
[Edited on 31-5-2006 by Joeychemist]
BeckhamStZ - 31-5-2006 at 02:29
Yes it's interesting ![;)](./images/smilies/wink.gif)
i know what is the end product but and the C is phenol but what is B !? and i don't know if C6H5Br + 2NaOH -> C6H5ONa +NaBr +H2O is true.
I know for chlorobenzene
but thanks
12AX7 - 31-5-2006 at 08:22
Yeah that's probably what's going on. If it were 1 NaOH, it would be phenol + NaBr, but it's 2 so it must be the salt.
Tim