Gioacchino - 11-11-2025 at 08:40
Hi, I need to do this exercise. I understand that the most reactive ring is the one on the right because its substituent is more activating than the
substituent attached to the left ring. Furthermore, it's an ortho/para-directing substituent. There's no problem with the ortho product, but with the
para product, I see that it's not possible to restore the ring's aromaticity. Will this para product still form?

DraconicAcid - 11-11-2025 at 08:48
No. The para position is taken already.
Gioacchino - 11-11-2025 at 09:46
Thank you very much