Sciencemadness Discussion Board

Electrophilic substitution reaction

Gioacchino - 11-11-2025 at 08:40

Hi, I need to do this exercise. I understand that the most reactive ring is the one on the right because its substituent is more activating than the substituent attached to the left ring. Furthermore, it's an ortho/para-directing substituent. There's no problem with the ortho product, but with the para product, I see that it's not possible to restore the ring's aromaticity. Will this para product still form?

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DraconicAcid - 11-11-2025 at 08:48

No. The para position is taken already.

Gioacchino - 11-11-2025 at 09:46

Thank you very much