mycotheologist - 22-5-2012 at 05:38
I'm aware that stannous chloride is commonly used as a selective reducing agent for reducing nitro groups to amino groups. Has anyone experimented
with stannous bromide or stannous iodide for this purpose?
UKnowNotWatUDo - 22-5-2012 at 05:57
I know tin(II) bromide is indeed a reducing agent as well. I assume it will also reduce nitro compounds to amines but this is just an assumption.
Obviously the easiest way to find out would be to spend some time googling or running some tests. Stannous bromide is easily prepared from powdered
tin metal and hydrobromic acid.
mycotheologist - 22-5-2012 at 06:04
Yeah I'm gonna prepare some since I have some 40% HBr lying around. Rather than powdered tin, I'll just use tin wire (lead free solder). Couldn't find
any info on the reducing agent properties of SnBr2 on google.
ScienceSquirrel - 22-5-2012 at 06:12
I suspect that they would as would all the other tin II salts.
The reducing property is due to the tin II ion, I doubt that the anion would have much effect.
UKnowNotWatUDo - 23-5-2012 at 19:33
Speaking of stannous chloride, does anyone have any detailed reaction mechanisms for the reductions?
woelen - 23-5-2012 at 23:23
The anion does have some effect, due to different complex formation properties. The redox properties of metals and their ions can be greatly affected
by the anions to which they are coordinated. I do not know the exact properties of the tin-complexes, but if you are researching reducing properties
of tin(II) salts, then also take into account the coordinating properties of the anion.