Sven - 31-5-2004 at 21:59
Hey guys,
Could someone help me out with the structure of the above compound?
Can't seem to find anything on the net for it.
I have a fair idea, just need some clarification. I believe it may be 2(phenyl) -- COH -- OMePhenyl. Or something like that anyway.
[Edited on 1-6-2004 by Sven]
t_Pyro - 1-6-2004 at 07:55
Carbinol is the -CH<sub>2</sub>OH group. Hence, in the given compound, the substituents are 2 phenyls, and one para-methoxyphenyl. My
guess would be something like:
p-MeO-Ph-C(OH)-(Ph)<sub>2</sub>
[Edited on 1-6-2004 by t_Pyro]