Quote: Originally posted by PHILOU Zrealone | If it is the anhydride of HO-SO2-O-SO2-OH (H2S2O7) thus (-O-SO2-O-SO2-)2 (or S4O12 or SO3)...
Then it will only display dehydrating abilities and catalytic effects (sulfuric anhydride or sulfur trioxide)
If it is the anhydride of HOO-SO2-OO-SO2-OH (H2S2O9 thus S4O16) ...
Then it is a peroxide and as such it will be unstable and a stong oxidizer...probably into the range of Mn2O7.
But does (SO4)4 or (SO4)n exist? |
I figured it could be useful as a chemical firestarter, given that it's basically H2SO4*SO3, and might be more manageable than the pure SO3 as an
oxidizer.
Is that not the case? |