bubbleboy - 26-3-2007 at 22:54
I recently recycled some triethylamine (by simple distillation) and the vast majority of it came over at 78-80C instead of the published boiling point
of 89C. What gives? Can anyone enlighten me please?
Also, instead of it being a water azeotrope, is it possible for TEA to form a constant boiling point mixture with a primary amine of a low boiling
point?
Do freebases form water azeotropes?
All input is welcomed. Thanks.
stoichiometric_steve - 27-3-2007 at 00:55
it's quite likely that, if you distilled from an aqueous mixture, your amine came over with steam. no azeotrope, just a simple steam distillation. you
should be getting two phases unless:
Solubility in water:
133 g/L (20°C)
you got other proportions.
leu - 27-3-2007 at 13:58
According British Patent 590713 one can separate the water-triethylamine azeotrope that boils at 75 ° C comprising 10% H2O using ethanol
Attachment: GB590713A.pdf (949kB)
This file has been downloaded 1164 times
bubbleboy - 27-3-2007 at 15:22
Leu, thank you so much. I owe you one.