Sciencemadness Discussion Board

hydrobromination alpha of ketone alpha,beta insaturate

Filemon - 4-12-2007 at 12:23

It may hydrobromize the double bond in alpha of ketone alpha, beta insaturate with peroxide? I believe that it may but I have not found any document it confirms.

JohnWW - 5-12-2007 at 05:50

I suggest that you look up the Markownikoff addition rule for addition of HF, HCl, HBr, and HI across double bonds in alkenes, in textbooks of organic chemistry, of which I have uploaded many (see the References section).

Filemon - 5-12-2007 at 13:07

It is not so simple. In this case the Markownikoff rule doesn't work. A ketone alpha, beta insaturate hydrobromine in beta.

JohnWW - 5-12-2007 at 18:38

Quote:
Originally posted by Filemon
It is not so simple. In this case the Markownikoff rule doesn't work. A ketone alpha, beta insaturate hydrobromine in beta.
In that case, the Anti-Markownikoff Rule, if other existing substituents on the alkene dictate otherwise.

chemrox - 5-12-2007 at 22:48

Might be that carbonyl provides the minute amount of O to make enough peroxide to force anti-Markovnikoff orinetation?? Is there a solvent effect? Does it matter whether solvent is protic? (I think I'm understanding but I could be way off the question too..) I'd like to see the diagrams and do the curved arrows..

Filemon - 6-12-2007 at 14:59

No, because the presence of the ketone it produces the nucleophilic is addition in beta.

http://en.wikipedia.org/wiki/Conjugate_addition

[Edited on 7-12-2007 by Filemon]

chemrox - 6-12-2007 at 23:29

OIC its Sn2 to the nucleophillic C beta to the carbonyl C due to the pi bond. I'm sorry there's a bit of a language barrier here and I sometimes need the stick figures to see what's going on. I should have drawn my own from what I discerned; shame on me. What ws your native tongue? I remember you told us but I forgot.

Nicodem - 7-12-2007 at 10:10

Quote:
Originally posted by Filemon
It may hydrobromize the double bond in alpha of ketone alpha, beta insaturate with peroxide? I believe that it may but I have not found any document it confirms.


I wish you would at least try to make your questions comprehensible. :(

I can only guess you want to know which position would the bromine radical add on an enone system?

The hydrobromination of alkenes in the presence of radical initiators proceeds by a radical chain mechanism in which Br° adds to the double bond in such a position as to form the most stabile C-radical possible. For example, the radical addition of HBr on isobutylene should give mostly isobutyl bromide and only little or no tert-butyl bromide. This is due to the intermediate Me<sub>2</sub>C°-CH<sub>2</sub>Br being more stabile than the other possible C-radical, Me<sub>2</sub>CBr-CH<sub>2</sub>° (see various tables for radicals thermodynamic stability).

In your substrate choice and its radical induced hydrobromination, the addition of Br on the enone position 4 should be prevalent due to the stabilizing effect of the carbonyl group alpha to the radical site (resonance stabilization). However, the ratio of the regioisomeric products depends on the groups located at the position 4 of the enone. If these groups are able to stabilize the radical more than the carbonyl group is able to, then you would get a different ratio of the two regioisomers. For example, in the case of Ph<sub>2</sub>C=CH-CO-Me you can expect the main product would be Ph<sub>2</sub>CH-CHBr-CO-Me since two phenyl groups stabilize the radical intermediate more than a carbonyl group would. Many complications can arise with such substrates and only a literature search can tell you if enones even react in radical addition reactions with HBr.

See also: http://en.wikipedia.org/wiki/Radical_addition

[Edited on 7/12/2007 by Nicodem]

Filemon - 10-12-2007 at 12:37

Quote:
Originally posted by chemrox
shame on me. What ws your native tongue? I remember you told us but I forgot.


I didn't say it. My language is Spanish.

Filemon - 10-12-2007 at 12:41

Thank you. Now I have understood that it can make. But it is necessary to choose a peroxide that it doesn't react with the ketone (Baeyer-Villeger oxidation).