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Rainwater
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They NaOH is an isolation step. As it helps react FexClx to oxides
If starting from pure metal, you should be able to go stright to the oxidizer.
Searching for a reference now. Its in one of these books
Edit: still searching, got at least 1 book for every unfinished project
[Edited on 28-3-2024 by Rainwater]
Not the book im looking for but should help
https://www.sciencemadness.org/talk/viewthread.php?tid=6896
[Edited on 28-3-2024 by Rainwater]
"You can't do that" - challenge accepted
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Chemgineer
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This looks promising, i'm getting an almost luminance orange colour now.
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fx-991ex
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Quote: Originally posted by Rainwater | They NaOH is an isolation step. As it helps react FexClx to oxides
If starting from pure metal, you should be able to go stright to the oxidizer.
Searching for a reference now. Its in one of these books
Edit: still searching, got at least 1 book for every unfinished project
[Edited on 28-3-2024 by Rainwater]
Not the book im looking for but should help
https://www.sciencemadness.org/talk/viewthread.php?tid=6896
[Edited on 28-3-2024 by Rainwater] |
Thats what am thinking too, once you oxidize the Cr it will stay in sln while the remaining metal-iron hydroxide precipitate will be discarded with
filtering.
React SS/Cr with acid - filter keep filtrate - react with carbonate(or bicarbonate?) - filter and keep precipitate - oxidize - filter and keep
filtrate - acidify to dichromate - react with KCl and keep precipitate.
[Edited on 28-3-2024 by fx-991ex]
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