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Author: Subject: Synthesis of para aromatic hydroxyls.
Triflic Acid
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[*] posted on 10-10-2020 at 21:30
Synthesis of para aromatic hydroxyls.


Chemicals like p-hydroxy-benzaldehyde, p-cresol, or 2-naphthol are often needed as building blocks in organic chemistry.
Would the following route work?

By first sulfonating the arene with H2SO4, an para aromatic sulfonic acid is obtained.

Removing the sulfonate group in molten NaOH gives a para aromatic alkoxide.

Acid workup gives the desired para hydroxy arene.

If it does work, it would be an OTC route to para aromatic hydroxyls, assuming that the initial arene is already available.
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[*] posted on 11-10-2020 at 14:31


Welcome to the forum!

p-Cresol, 1- and 2- naphthols are readily prepared by the process of alkali fusion with the sodium salt of the sulphonic acid but I don't think you can prepare p-(4-)-hydroxybenzaldehyde by this process (it is usually prepared by the thermal rearrangement of salicylaldehyde). I don't think the aldehyde group will survive such brutal treatment; I think that it will either oxidize or undergro a Cannizzaro like reaction.

This reaction is an industrially important one and has been very well studied. I have numerous classic textbook on the preparation of dye intermediates and reading them makes it clear that the reaction is complex with many unexpected results. Furthermore it is not a very amateur-friendly technique. I would suggest you read up about some of the standard laboratory procedures (try Vogel for starters) and consider the equipment you are going to use. For instance, how are you going to protect the delicate thermometer bulb from the extemely corrosive fused alkali? Do you have a steel clad thermocouple? etc.

There are several tread on this forum by guys that have used this procedure to prepare phenol or resorcinol. I suggest you read them before attempting it yourself
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[*] posted on 11-10-2020 at 19:23


Why would I need a thermometer in the first place, just an IR one should be good enough from a distance?
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[*] posted on 11-10-2020 at 19:28


Maybe a protecting acetal group would stop the Cannizzaro? And what would cause it to oxidize?
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[*] posted on 12-10-2020 at 15:10


p hydroxybenzaldehyde was my main goal in this synthesis, so I want to find a route to that.
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[*] posted on 13-10-2020 at 04:45


Most methods of aldehyde formation (formylation) from phenol yield the p- isomer. The Rimmer Tiemann reaction is an exception but apparently you can convert the o- isomer into the p-isomer. There are vast numbers of references to its preparation, including many patents.
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[*] posted on 13-10-2020 at 05:45


P-hydroxy benzaldehyde may be obtained by the cleavage of anethole to p-methoxybenzaldehyde and demethylation — these reactions are somewhat well-developed among amateur chemists



[Edited on 04-20-1969 by clearly_not_atara]
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[*] posted on 13-10-2020 at 07:00


Can you put a link to the forum with the procedures? I couldn't find any
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[*] posted on 13-10-2020 at 16:18


Quote: Originally posted by Boffis  
Most methods of aldehyde formation (formylation) from phenol yield the p- isomer. The Rimmer Tiemann reaction is an exception but apparently you can convert the o- isomer into the p-isomer. There are vast numbers of references to its preparation, including many patents.
I don't know what you mean by "most methods" as the main two that could accomplish formylation of phenol directly are the Reimer-Tiemann and the Duff reaction, both of which would yield salicylaldehyde. The Vilsmeier-Haack is less accessible for amateurs, and would require the phenol to be protected in order to be employed, and unless you use a very bulky protecting group that would sterically disfavor o-substitution, you'll probably get primarily o-formylation or a mixture with that too.

Bouveault aldehyde synthesis is another option, though for that you'd need to make p-chlorophenol, which shouldn't be too difficult, but would require carefully controlled chlorination of phenol to ensure that you don't overchlorinate.




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[*] posted on 14-10-2020 at 13:16


Check this link but it is in chinese: https://patents.google.com/patent/CN102992982B/en?q=p-hydrox...
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[*] posted on 14-10-2020 at 17:26


Quote: Originally posted by Triflic Acid  
Can you put a link to the forum with the procedures? I couldn't find any


Sorry, this procedure used to be famous for using anethole as a precursor to mequinol, but apparently it is no longer so well-known (as the prep of mequinol from hydroquinone has become better):

https://erowid.org/archive/rhodium/pdf/anethole.2c-b.pdf

Only the first reaction taking anethole to anisal is relevant for you, the rest are irrelevant.

Then for the demethylation it is a little harder, maybe you can use one part 48% HBr to three parts GAA, but I'm not sure if anisal will dissolve -- hopefully you can avoid gassing HBr as it is annoying... but HBr is the reagent of choice IMO for any substrate that will stand up to it, because it is just so much easier to get/make than anything else.




[Edited on 04-20-1969 by clearly_not_atara]
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[*] posted on 15-10-2020 at 09:10


For the paper I posted, the translation says to use a reagent I, not sure if this is iodine or something else. If it is iodine, its a really accessible synthesis.
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[*] posted on 15-10-2020 at 09:16


It says right in the abstract that the reagent is a Vilsmeier reagent. See Vilsmeier-Haack reaction.

Edit: See, you should have read a little farther: "In described step (1), reagent I is POCl3 or SOCl2 or PCl5 or PCl3" Typical Vilsmeier-Haack conditions.

If you can't even be bothered to read the paper you're asking about, this is getting into pure spoonfeeding territory.

[Edited on 10-15-2020 by Texium (zts16)]




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[*] posted on 15-10-2020 at 10:56


Where was that written?
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[*] posted on 15-10-2020 at 10:59


Oh, I didn't see the translation beneath that
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[*] posted on 15-10-2020 at 11:02


I tried to translate the paper into english using google translate, and it only gave me some parts of the paper.
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[*] posted on 15-10-2020 at 12:54


Also, I knew that that was a Vilsmeier reagent, that's why I posted it.
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[*] posted on 15-10-2020 at 13:45


Boffis, Texium: I am surprised you have both omitted the most famous phenol formylation, the Mg(OMe)2 method... this too is mostly ortho of course.

The term "Vilsmeier reagent" to me always referred to the chloroiminium produced by the rxn of POCl3/SOCl2/COCl2 with DMF. Unfortunately it is very hard to produce this kind of reagent without phosphorus compounds or SOCl2. It is higher in energy than something like Ac2O.

More generally, reactions with weak electrophiles that attack the phenolate anion, which is most of the easy methods, will usually go to the ortho position. Reactions with strong electrophiles that attack neutral phenol will go mostly to para.

So Vilsmeier, Gattermann, formyl fluoride all go to para, while Reimer-Tiemann and Mg/HCHO go to ortho. Duff goes to ortho because of hydrogen bonding.

The Gattermann reaction with Zn(CN)2/HCl is the most likely to be accessible to amateurs in terms of reagents, but the risks associated with improper operation of the apparatus when you gas zinc cyanide with HCl are not appropriate for a new chemist.

The method from anethole is much safer.

[Edited on 15-10-2020 by clearly_not_atara]




[Edited on 04-20-1969 by clearly_not_atara]
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[*] posted on 23-10-2020 at 16:06


No one has answered my question yet, is there a protecting group that will keep the aldehyde in benzaldehyde from being cannizaro-ed when it is in molten NaOH or some other OH. I read somewhere on the forum that a much lower melting KOH and NaOH mix is possible.
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[*] posted on 23-10-2020 at 19:29


An ethylene or propylene glycol acetal might work, and is very easy to prepare.

Screen Shot 2020-10-23 at 9.18.51 PM.png - 254kB
I found this excerpt from a book about the pyrolysis of various organic molecules. Acetals are well-known to be stable to strong bases, and apparently they are pretty stable to high temperatures as well, considering this book reports heating the propylene glycol acetal of vanillin to 700ºC (!) for 20 minutes, which is a much higher temperature than you would need, and still recovering nearly 23% of the starting material. At the lower temperature that you would be exposing it to, there should be considerably less decomposition. They do note, however, that at 250ºC in the presence of moisture, the acetal will decompose to the aldehyde and the glycol, so you will need to make sure that your hydroxide is as fresh and dry as possible if you do this.

Source: https://www.sciencedirect.com/science/article/pii/B978044464...




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[*] posted on 23-10-2020 at 21:01


Quote: Originally posted by clearly_not_atara  
Boffis, Texium: I am surprised you have both omitted the most famous phenol formylation, the Mg(OMe)2 method... this too is mostly ortho of course.
This is what I get for spending too much time in academia away from amateur chemistry.



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[*] posted on 24-10-2020 at 21:35


Does anyone know about the KOH NaOH mixture with a low melting point? Also, how do you keep moisture away from the acetal? I'm thinking that maybe having some molten Na in the mix might destroy any water, turning it into NaOH.
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[*] posted on 25-10-2020 at 06:20


Look up NaOH+KOH eutectic mixture. You do not need to keep moisture away from the acetal unless you are using it under those conditions. You can dry NaOH and presumably KOH by drying in an oven until a constant mass is achieved, then by melting and holding above 260 C.
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[*] posted on 25-10-2020 at 08:32


So, this would be the synthesis of p-hydroxybenzaldehyde,


p-hydroxybenzaldehyde.png - 39kB

[Edited on 25-10-2020 by Triflic Acid]
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