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Author: Subject: Solubility of hydrated salts compared to their anhydrates
teodor
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[*] posted on 3-11-2022 at 07:59


Quote: Originally posted by SnailsAttack  
And what properties determine this equilibrium? The mass of the solute and the mass of the solvent. That's just the mass ratio between the water and the salt. There shouldn't be any discrepancies.


Did you check the image I've attached here for Na2SO4 * 7H2O, Na2SO4 * 10H2O? At the same temperature there are 2 values for the solubility, you can use a ruler to check that. So, if you try to measure the solution in equilibrium with solid Na2SO4 * 7H2O it becomes supersaturated in relation to Na2SO4 * 10H2O.
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