Sciencemadness Discussion Board » Fundamentals » Beginnings » Law of mass action? Select A Forum Fundamentals   » Chemistry in General   » Organic Chemistry   » Beginnings   » Responsible Practices   » Miscellaneous Engineering and Equipment   » Reagents and Apparatus Acquisition   » Electronics   » Process Engineering   » Materials and Metallurgy Special Topics   » Analytical Chemistry   » Electrochemistry   » Energetic Materials   » Biochemistry   » Radiochemistry   » Computational Models and Techniques Literature and Documentation   » Sciencemadness Wiki   » Prepublication Non-science   » Forum Matters   » Legal and Societal Issues

Author: Subject: Law of mass action?
Wolfram
Hazard to Others

Posts: 133
Registered: 13-10-2003
Member Is Offline

Mood: No Mood

Law of mass action?

Sorry it was some years ago that I worked with fundamental chemisty could you help me?

I have the follwing equation:

d[AR]/dt=k1([A]-[AR])([R]-[AR])-k2([AR])

It describes the change in concentration of a receptor (R) a agonsist a and a
receptor-agonist complex (AR). But how is it with the formal calculations?
If the expression k1([A]-[AR])([R]-[AR]) should result in a M^2 unit
how could this be substracted from k2([AR]) which is a M^1 unit?

Have I missed something?

Thank you for any help
Magpie
lab constructor

Posts: 5939
Registered: 1-11-2003
Location: USA
Member Is Offline

Mood: Chemistry: the subtle science.

It has been some time for me also but I believe that any disparity in the units is provided for by the different units of the rate constants k1 and k2.

The single most important condition for a successful synthesis is good mixing - Nicodem
Ozone
International Hazard

Posts: 1269
Registered: 28-7-2005
Location: Good Olde USA
Member Is Offline

Mood: Integrated

It should all work out to mol/s-1. In your derivation there should be a Mo (starting moles) and an M (moles at some differential time, t.

I'll give this some more attention (I have worked this out in the last year or so) tomorrow when I have had some rest (I have it on paper, but am too tired to transcribe (or manually derive) it here).

Good night,

O3

-Anyone who never made a mistake never tried anything new.
--Albert Einstein

 Sciencemadness Discussion Board » Fundamentals » Beginnings » Law of mass action? Select A Forum Fundamentals   » Chemistry in General   » Organic Chemistry   » Beginnings   » Responsible Practices   » Miscellaneous Engineering and Equipment   » Reagents and Apparatus Acquisition   » Electronics   » Process Engineering   » Materials and Metallurgy Special Topics   » Analytical Chemistry   » Electrochemistry   » Energetic Materials   » Biochemistry   » Radiochemistry   » Computational Models and Techniques Literature and Documentation   » Sciencemadness Wiki   » Prepublication Non-science   » Forum Matters   » Legal and Societal Issues