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Cr(IV) Configuration?Known Complex?
Assuming(it's a fact .. .:-) Chromium is [Ar]4s^1 3d^5 , what configuration does Cr(IV) have? [Ar] 3 ... |
13-12-2005 at 08:05
by: NoSpoon |
Spinel (unknown cation)
yeah I'm sure  unfortunately... otherwise I would't have asked for help ....
but thx anyway, yo ... |
13-12-2005 at 07:57
by: NoSpoon |
Spinel (unknown cation)
[quote]
2.74 / (2*0.685) = 2, so the ration of Al vs O = 2, which is what we want.
[/quote]
but ... |
12-12-2005 at 10:51
by: NoSpoon |
Spinel (unknown cation)
unfortunately not close enough ... i tried ... an I'm still trying  |
12-12-2005 at 07:05
by: NoSpoon |
"smart material" - no equilibrium
the reaction is called somethin like iodineclock-reaction .. it will eventually stop sometime ... th ... |
12-12-2005 at 07:04
by: NoSpoon |
Spinel (unknown cation)
yeah, but then try to calculate .. I get SiAl2O4 and that doesn't exist does it?
do you know what ... |
11-12-2005 at 14:49
by: NoSpoon |
Spinel (unknown cation)
thx for your help,
I could say the 37.6 grams must contain another 0.68 moles of Al(since a spine ... |
11-12-2005 at 14:16
by: NoSpoon |
Spinel (unknown cation)
well, I have a Spinell that is made of 43.9%oxygen, 18.5%aluminum and 37.6%unknown cations(mass-perc ... |
11-12-2005 at 11:45
by: NoSpoon |
