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Well duh
Buffer I; pH = 4.7 + log([20E-3]/[5E-3]) = 5.3

Buffer II; pH = 4.7 + log ([40E-3]/[40E-3]) = 4.7
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4-11-2005 at 03:38
by: collisoo
Calculating pH
Given that the pKa of acetic acid is 4.7, what are the pH values of the three buffers? Satisfy yours ...
3-11-2005 at 05:53
by: collisoo

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