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Author: Subject: Oxidation- Reduction
crazyheaven
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[*] posted on 6-8-2008 at 02:07
Oxidation- Reduction

What happens if MnO2 was mixed with KI and 9M sulfuric acid?

Can't seem to figure this one out.

[Edited on 6-8-2008 by crazyheaven]
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woelen
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[*] posted on 6-8-2008 at 02:26


The MnO2 will oxidize the iodide to iodine:

MnO2 + 4H(+) + 2I(-) --> Mn(2+) + I2 + 2H2O

At a concentration of 9M for the sulphuric acid, I also can imagine that the acid itself may be oxidizing the iodide to some extent as well, making the reaction less clean (production of sulphur, hydrogen sulfide and sulphur dioxide). I would suggest to decrease the concentration of the acid to 4M or something like that. At such a lower concentration the only reaction will be the one, given above.



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crazyheaven
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[*] posted on 6-8-2008 at 02:32


Thank you for the help. Didn't think I'd get such a fast reply.

Seems I would be able to learn a lot from this site.
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