Sciencemadness Discussion Board
Not logged in [Login ]
Search the forums Search   Frequently Asked Questions FAQ   View member list Member List   Today's Posts Today's Posts   Forum Stats Stats Back to: sciencemadness.org
Sciencemadness Discussion Board » Fundamentals » Beginnings » Oxidation- Reduction Go To Bottom

Printable Version  
Author: Subject: Oxidation- Reduction
crazyheaven
Harmless
*



Posts: 2
Registered: 6-8-2008
Member Is Offline

Mood: No Mood

[*] posted on 6-8-2008 at 02:07
Oxidation- Reduction

What happens if MnO2 was mixed with KI and 9M sulfuric acid?

Can't seem to figure this one out.

[Edited on 6-8-2008 by crazyheaven]
View user's profile View All Posts By User
woelen
Super Administrator
*********



Posts: 7978
Registered: 20-8-2005
Location: Netherlands
Member Is Offline

Mood: interested

[*] posted on 6-8-2008 at 02:26


The MnO2 will oxidize the iodide to iodine:

MnO2 + 4H(+) + 2I(-) --> Mn(2+) + I2 + 2H2O

At a concentration of 9M for the sulphuric acid, I also can imagine that the acid itself may be oxidizing the iodide to some extent as well, making the reaction less clean (production of sulphur, hydrogen sulfide and sulphur dioxide). I would suggest to decrease the concentration of the acid to 4M or something like that. At such a lower concentration the only reaction will be the one, given above.



The art of wondering makes life worth living...
Want to wonder? Look at https://woelen.homescience.net
View user's profile Visit user's homepage View All Posts By User
crazyheaven
Harmless
*



Posts: 2
Registered: 6-8-2008
Member Is Offline

Mood: No Mood

[*] posted on 6-8-2008 at 02:32


Thank you for the help. Didn't think I'd get such a fast reply.

Seems I would be able to learn a lot from this site.
View user's profile View All Posts By User

 Sciencemadness Discussion Board » Fundamentals » Beginnings » Oxidation- Reduction   Go To Top