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fresher_007
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[*] posted on 12-3-2010 at 02:20
veratric acid


which is the best route for preparation of veratric acid????????
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JohnWW
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[*] posted on 12-3-2010 at 02:31


If you already have veratrole, it would be by some sort of oxidation, the reagent chosen depending on the functional groups to be considered.
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fresher_007
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[*] posted on 12-3-2010 at 02:48


i have veratrole......

but what will be the reagent
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not_important
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[*] posted on 12-3-2010 at 03:04


Veratrole is just 1,2-Dimethoxybenzene, you need to get a carbon on the ring at the 4- position.

You might do easier by oxidising vanillin to vanillc acid, and the methylating that; or methylating vanillin and oxidising it.

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fresher_007
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[*] posted on 12-3-2010 at 03:13


ok.....

i will try......

but any other route.... available......
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JohnWW
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[*] posted on 12-3-2010 at 03:39


Veratrole is 1,2-dimethoxybenzene, C6H4(OCH3)2, see http://en.wikipedia.org/wiki/1,2-Dimethoxybenzene. It is slightly soluble in water, but miscible in all organic solvents.

HOWEVER, despite the nomenclature, veratric acid, which is 3,4 dimethoxybenzoic acid, CANNOT be directly made from veratrole by oxidation; instead, it has to be via "veratrole alcohol", which is 3,4-dimethoxybenzylalcohol, see http://en.wikipedia.org/wiki/Veratrole_alcohol , or veratraldehyde, which is 3,4-dimethoxybenzaldehyde, http://en.wikipedia.org/wiki/Veratraldehyde , or by some other suitable oxidizable substituted derivative of veratrole, and then by oxidation. This would require a -CH2OH or -CHO or alkyl group to be added to the benzene ring, meta to one of the -OCH3 groups and para to the other.

A way of doing this, to obtain the aldehyde, appears to be by Friedel-Crafts acylation, using chloroformaldehyde, HClC=O, with usually AlCl3 or FeCl3, in a polar organic solvent at about 80ºC:
C6H4(OCH3)2 + HClC=O ---[AlCl3]----> C6H3(OCH3)2CHO + HCl
However, HClC=O is likely to be, like COCl2, very volatile (probably a gas at reaction conditions) and highly poisonous, and not easy to come by or to generate in situ.

Alternatively, and much more conveniently, an alkyl group, theoretically any such group, could be added by Friedel-Crafts alkylation, using any alkyl chloride RCH2Cl:
C6H4(OCH3)2 + RCH2Cl ---[AlCl3]----> C6H3(OCH3)2CH2R + HCl

Then this product can be oxidized in high yield with KMnO4 to obtain veratric acid:
C6H3(OCH3)2CH2R ---[KMnO4--> CH3(OCH3)2COOH

Another problem is that some of the isomer with the -CHO or alkyl group ortho to one of the -OCH3 group is likely to be produced by the Friedel-Crafts reaction, but it is not clear how much. The isomeric alkyl derivatives, or the acids, may require chromatographic separation. There is also the possibility of more than one such -CHO or alkyl group being introduced to the ring.

[Edited on 12-3-10 by JohnWW]
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UnintentionalChaos
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[*] posted on 12-3-2010 at 04:30


Use vanillin. It's cheap, easy to get, and most of the work is already done.

5 seconds on google found this: http://www.orgsyn.org/orgsyn/orgsyn/prepContent.asp?prep=cv2...

A similar procedure is probably applicable with methyl iodide, methyl tosylate, or the methyl ethanesulfonate that we have a prep somewhere on this forum for.

Oxidation of an aldehyde to a carboxylic acid is an easy transformation in the scheme of things. Most people would prefer to go the opposite direction with such ease, I imagine. Any moderately strong oxidizing agent will do the job for you. Even bleach would probably be fine if that's really all that you had.

JohnWWW- formyl chloride is unknown except under extreme conditions (and maybe not even then, it's been a while since I looked), IIRC. It prefers to exist as a mixture of CO and HCl and is thus worthless for synthesis.

Due to sterics, FC acylation of o-dimethoxybenzene with methyl chloroformate would probably furnish the desired acid as the methyl ester. methyl chloroformate is not quite as horrible as phosgene, but still not a walk in the park. Heavier alcohols would be even more advantageous to strap the chloroformyl moiety to, decreasing volatility. Avoid tert-butyl as hydrolysis is rather more difficult.

[Edited on 3-12-10 by UnintentionalChaos]




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entropy51
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[*] posted on 12-3-2010 at 06:35


Quote: Originally posted by UnintentionalChaos  
JohnWWW- formyl chloride is unknown except under extreme conditions (and maybe not even then, it's been a while since I looked), IIRC. It prefers to exist as a mixture of CO and HCl and is thus worthless for synthesis.
Well, it's not useless. It's the Gatterman aldehyde synthesis, wherein the aromatic hydrocarbon and AlCl3 is indeed gassed with CO and HCl. A modification uses zinc cyanide instead of CO. Only certain aromatics will react. No matter how you do them, they are a pain in the tush.
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not_important
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[*] posted on 12-3-2010 at 07:51


And then there's chloromethylation, using HCl, formaldehyde, and a catalyst - ZnCl2 for benzene and toluene. Chloromethylether can be used instead, as in The Chloromethylation of Veratrole

http://pubs.acs.org/doi/abs/10.1021/ja01170a508

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[*] posted on 12-3-2010 at 10:11


Formylation by Freidel crafts Acylation can be achieved by formyl fluoride or pehaps even formic-acetic anhydride. However I would expecct a mix of two isomers to form. Friedel Crafts Alkylation is limited in so far as it's hard to control and generally gives a peralkylated product; I'd expect this problem to be escalated by the fact that all of the unsubstituted positions on the ring are activated by the methoxy groups.
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[*] posted on 13-3-2010 at 12:18


Methylation of eugenol followed by oxidation with chromic acid or permanganate is also an option



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