Freezing point depression is a colligative property. It is dependent on the total concentration of solute particles in solution, regardless
of their identity. CaCl2 dissociates into three ions when it dissolves, so it is 1.5 times as potent per mole of salt as NaCl or
NH4NO3.
If you made solutions of equal concentration of those three salts, the CaCl2 would have the lowest freezing point, and the NaCl and
NH4NO3 would have equal freezing points. So solubility is important of course, since higher concentration = lower freezing
point, but high solubility combined with more ions in solution is especially good.
Endothermic dissolution is important so that your solution gets colder as the salt dissolves, but it’s independent from what the magnitude of the
freezing point depression is.
I’d be curious to see how cold you can get a mixture with AlCl3•6H2O since it splits into 4 ions, though it doesn’t have
quite as high solubility.
Also, very nice post overall! Thank you for sharing your write-up. |