Gioacchino
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Electrophilic substitution reaction
Hi, I need to do this exercise. I understand that the most reactive ring is the one on the right because its substituent is more activating than the
substituent attached to the left ring. Furthermore, it's an ortho/para-directing substituent. There's no problem with the ortho product, but with the
para product, I see that it's not possible to restore the ring's aromaticity. Will this para product still form?
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DraconicAcid
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No. The para position is taken already.
Please remember: "Filtrate" is not a verb.
Write up your lab reports the way your instructor wants them, not the way your ex-instructor wants them.
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Gioacchino
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Thank you very much
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