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Author: Subject: (R-OH →) R-Cl → RH (one pot? amine presence?)
bromosapien
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[*] posted on 28-2-2026 at 15:09
(R-OH →) R-Cl → RH (one pot? amine presence?)


So, I've found a good bit of info already, especially the primary alcohol sn2 to halide, with Lucas catalyst in the case of Chloride... but unfortunately almost every resource is geared entirely toward just teaching the mechanism to students, with zero experimental hints as far as ratios, conditions, etc... so I'm hoping some of you nerds can give me some pointers.

Ideally I'd like to arrive at procedure that could work for amino alcohols from reduced amino acids. In theory I want to believe that I can just protonate the amine in aq HCl, add another eq+ of HCl and some zinc to sn2 the primary OH to Cl, then add more zinc maybe more HCl, and reflux for a while to reduce Cl to H. But my gut says in practice it's not going to be easy.

Does anyone have experience with any part of this? For any substrates, not just amino alcohols... A one-pot SN2 + reduction of primary OH would be really cool. I just want a little info on what parts of the reaction may require water removal, large excess of one reagent over another... practical tips on what to try.

I worry a little bit about the 'amino alkyl halide' polymerizing or forming the aziridine, although that is interesting and maybe useful in its own right. But it seems that it should be possible to at least slow that down, or set it up so the zinc has a good chance of reducing it first.

[Edited on 28-2-2026 by bromosapien]
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Alchemica
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[*] posted on 1-3-2026 at 10:33


Here's some info on Lucas Reagent and some preparative procedures that may be of interest to you

My [still learning, with plenty of room for improvement] personal opinion is that if the RX to RH reduction was in a sufficiently acidic medium to keep the amine fully protonated eg -NH3+Cl-, the nucleophilicity of the amine would not be problematic enough to allow rapid aziridine formation through easy nitrogen alkylation and as long as most RX is dehalogenated prior to work-up, may work? While things like Mg/iPrOH etc dehalogenations [see: https://orgsyn.org/Content/pdfs/procedures/CV5P0998.pdf ] are seemingly great ways to remove halogens, I wonder if the non-acidic reaction mixture might enhance risk of aziridine formation vs Zn/acid systems









butyl chloride hcl zncl2.jpg - 176kBrx to rh zn acoh.jpg - 83kB

Attachment: lucas reagent.pdf (3.1MB)
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bromosapien
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[*] posted on 1-3-2026 at 15:41


Thank you Alchemica! That material is immensely helpful, exactly what I wanted!

The magnesium method also interests me, but I had the same concerns (I'm also very much "still learning...") because it essentially proceeds through formation of a Grignard thing, yes? But that is definitely interesting and going directly to my PDF collection for later!

I'm curious what books those are from, and looking for book recommendations for this kind of information - I have no issues finding great educational material for the theory, but I struggle to find good practical preparatory guides.
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[*] posted on 1-3-2026 at 15:47


Take a look at the Library (link below in my signature).



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Alchemica
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[*] posted on 1-3-2026 at 17:02


Most welcome. Sorry I saved screenshots that weren't properly referenced my end. Have a feeling the first pic was Norris (see pdf attached), while the second was Weygand and Hilgetag Preparative Organic Chemistry but that's too big a pdf to attach here. Let me know via message if you have troubles locating a pdf.

Vogel's Practical Organic Chemistry is definitely one to have on hand, too



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bromosapien
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[*] posted on 1-3-2026 at 17:48


Wonderful, thank you guys!

Something I have noticed is that these procedures always seem to call for anhydrous zncl2 even though they involve addition of aqueous HCl... is that something I really need to pay special attention to?

I may actually be trying reduction of acids to alcohols with Zinc Borohydride (10.1021/jo00121a060), which definitely requires anhydrous ZnCl2 so I'll be geting / making some anyway. But it's puzzling.
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Alchemica
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[*] posted on 1-3-2026 at 18:46


Definitely anhydrous is the way to go, don't want to be diluting your reaction mixture to even lower [H+] and [Cl-] with hydrated ZnCl2. Mixing anhydrous ZnCl2 with 36% HCl is very exothermic and evolves quite a bit of HCl gas, so ice bath cooling, stirring etc seem important.

I've seen NaBH4/I2 (think THF used as solvent) for simple, high yielding undergrad reductions of amino acids to amino alcohols, so don't neglect that
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[*] posted on 1-3-2026 at 22:16


Hell yes. Thanks for the spoonfeeding-adjacent help, you have saved me so much time and given me a lot of fun reading!!!
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Alchemica
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[*] posted on 2-3-2026 at 16:54


All good, happy to help. BTW I find reading e-EROS - The Encyclopedia of Reagents for Organic Synthesis - to be a good start to get some ideas and further references for whatever reagent you want to utilise

It's detailed information on more than 5,250 reagents and catalysts, and every year up to 200 new or updated articles are added in order to keep the Database up-to-date. https://onlinelibrary.wiley.com/doi/book/10.1002/047084289X

Don't have a full pdf of it I've been able to locate so I just sci-hub.st the individual reagent articles of interest

Good luck, nothing too nefarious in your organic chemistry projects please.



[Edited on 3-3-2026 by Alchemica]
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[*] posted on 3-3-2026 at 19:10


Seems to me I've seen such a procedure, but it involves replacing that -OH group with Iodine, and reducing the product with Zn.

Of course, the reduction of Ephedrine via HI from I2 and Red Phosphorus, is well known.

But, in that case the -OH to be replaced by H, happens to be placed on a Benzylic Carbon atom. The stability of that particular Carbonium Ion, allows OH to be replaced by I, and then it allows the I to be replaced by H. This later action being more or less irreversible.

OH may also be removed via Toluene Sulfonyl-Chloride? Under these somewhat unique conditions -OH becomes a good leaving group via hydrogenation. Problems? The amino group may require protection during the procedure. Expensive, hard to obtain reagents may be required.
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[*] posted on 12-3-2026 at 18:45


Quote: Originally posted by zed  
Seems to me I've seen such a procedure, but it involves replacing that -OH group with Iodine, and reducing the product with Zn.

Of course, the reduction of Ephedrine via HI from I2 and Red Phosphorus, is well known.

But, in that case the -OH to be replaced by H, happens to be placed on a Benzylic Carbon atom. The stability of that particular Carbonium Ion, allows OH to be replaced by I, and then it allows the I to be replaced by H. This later action being more or less irreversible.

OH may also be removed via Toluene Sulfonyl-Chloride? Under these somewhat unique conditions -OH becomes a good leaving group via hydrogenation. Problems? The amino group may require protection during the procedure. Expensive, hard to obtain reagents may be required.


Yeah, even if the Nagai worked I'm not interested in it, I'm really hoping to find a route that only uses Zinc and HCl gas. I also fear the 'amino alkyl iodide' would be more prone to polymerize or make the aziridine. If I have trouble with HCl I may try with HBr.
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[*] posted on 13-3-2026 at 15:32


I believe a procedure exists using hydrochloric acid with Pd and H2. This would satisfy the conditions but it does of course involve palladium. Unlike most other metals, Pd is somewhat resistant to oxidation by protons.



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[*] posted on 16-3-2026 at 23:11


Quote: Originally posted by clearly_not_atara  
I believe a procedure exists using hydrochloric acid with Pd and H2. This would satisfy the conditions but it does of course involve palladium. Unlike most other metals, Pd is somewhat resistant to oxidation by protons.


Have you (or has anyone here) experience with Raney Ni? From my reading, you can usually substitute it for pd/c at the cost of yield.

Also - If I understand correctly, alcohol Sn2 with HX proceeds through a carbocation, yes... would this lead to rearrangement in the case of a beta hydroxyl amine? Which could actually be beneficial if the end goal is to remove the hydroxyl, however, could it then lead to racemization in some cases?
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[*] posted on 17-3-2026 at 16:16


Raney Ni is not compatible with HCl. It will be attacked. In this case, it can't substitute.



Quote: Originally posted by bnull  
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