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Author: Subject: Al + NH4Cl
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[*] posted on 30-9-2006 at 14:49
Al + NH4Cl


What does it take place reaction? Al + NH4Cl => AlCl3 + NH3 + H2?
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[*] posted on 30-9-2006 at 20:10


Yeah, that seems reasonable. Note that NH4Cl <--> NH3 + HCl (decomposition, not sublimation). This also fights with AlCl3 sublimation, and (though probably at higher temperatures) NH3 + Al = AlN + 3H (1.5 H2).

So hmm, you get NH4Cl --> NH3 + HCl at high temperature. Mixed with aluminum (filings, turnings, powder?) the reaction Al + 3HCl --> AlCl3 + 1.5 H2 takes place; AFAIK, H2 is never a strong enough reducing agent vs. aluminum, so this reaction is strongly to the right. Therefore, the reaction 3NH4Cl + Al = 3NH3 + AlCl3 + 1.5 H2 must proceed.

This sounds like a suspiciously good way to make AlCl3, what's wrong with it?

Tim




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[*] posted on 30-9-2006 at 22:50


It works, but A) it is difficult to separate unreacted NH4Cl from AlCl3, and B) AlCl3 and NH3 form a complex

1st page on complex
http://pubs.acs.org/cgi-bin/abstract.cgi/inocaj/1975/14/i06/...
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