cazruto
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hi H2N-(CH2)5-COOK
H2N-(CH2)5-COOH + KOH = H2N-(CH2)5-COOK hi is it possible ?
oololoo
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Nicodem
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Thread Moved
29-6-2012 at 22:55 |
Hexavalent
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Possibly, I suspect that with correct stoichiometry a simple acid/base neutralization would take place to produce the salt you mention and water.
For reference - H2N-(CH2)5-COOH is 6-aminoacetic acid
and
H2N-(CH2)5-COOK is potassium 6-aminoacetate.
EDITED to correct the IUPAC name for the 'H2N-(CH2)5-COOH'.
[Edited on 30-6-2012 by Hexavalent]
"Success is going from failure to failure without loss of enthusiasm." Winston Churchill
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kavu
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Did you catch the 5 in methylenes. It's aminocaproic acid or in IUPAC 6-aminohexanoic acid. As for the reaction, it does proceed as you suspected. KOH
is strong enough base to overcome the buffering effect of the zwitterion.
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